What are the solutions to the equation r^2+8r-9=0 ?

The solutions to the equation r^2+8r-9=0 are r=1,r=-9

Find the zeros of r^2+8r-9=0

The zeros of r^2+8r-9=0 are r=1,r=-9

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r^{2} + 8 r - 9 = 0

r = 1, r = - 9

Solution steps

r^{2} + 8 r - 9 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

r_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 10}{2 \cdot 1}, r_{2} = \frac{- 8 - 10}{2 \cdot 1}

r = \frac{- 8 + 10}{2 \cdot 1} : 1

r = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

r = 1, r = - 9

\frac{x}{7} - \frac{x}{9} = 5

(- \frac{3}{2})^{2}

8 c^{3} + 1

lo g_{5} (x) = 3

12.5

What are the solutions to the equation r^2+8r-9=0 ?
The solutions to the equation r^2+8r-9=0 are r=1,r=-9
Find the zeros of r^2+8r-9=0
The zeros of r^2+8r-9=0 are r=1,r=-9