What are the solutions to the equation -x^2-2x-3=0 ?

The solutions to the equation -x^2-2x-3=0 are x=-1-sqrt(2)i,x=-1+sqrt(2)i

Find the zeros of -x^2-2x-3=0

The zeros of -x^2-2x-3=0 are x=-1-sqrt(2)i,x=-1+sqrt(2)i

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- x^{2} - 2 x - 3 = 0

x = - 1 - 2 i, x = - 1 + 2 i

Solution steps

- x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

(- 2)^{2} - 4 (- 1) (- 3) : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2 2 i}{2 ( - 1 )} : - 1 - 2 i

x = \frac{- ( - 2 ) - 2 2 i}{2 ( - 1 )} : - 1 + 2 i

The solutions to the quadratic equation are:

x = - 1 - 2 i, x = - 1 + 2 i

5 + 3.2 n - 6 - 4.8 n

∣ x + 4 ∣ + 7 = 3

7 = x + 4

lo g_{3} (8) - 2 lo g_{3} (36) + lo g_{3} (6)

\frac{n + 6}{n ^{2} + 8 n + 12}

What are the solutions to the equation -x^2-2x-3=0 ?
The solutions to the equation -x^2-2x-3=0 are x=-1-sqrt(2)i,x=-1+sqrt(2)i
Find the zeros of -x^2-2x-3=0
The zeros of -x^2-2x-3=0 are x=-1-sqrt(2)i,x=-1+sqrt(2)i