What are the solutions to the equation 1+0.4x-0.45x^2=0 ?

The solutions to the equation 1+0.4x-0.45x^2=0 are x=-10/9 ,x=2

Find the zeros of 1+0.4x-0.45x^2=0

The zeros of 1+0.4x-0.45x^2=0 are x=-10/9 ,x=2

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1 + 0.4 x - 0.45 x^{2} = 0

x = - \frac{10}{9}, x = 2

Decimal Notation

x = - 1.11111 \dots, x = 2

Solution steps

1 + 0.4 x - 0.45 x^{2} = 0

Multiply both sides by

100

100 + 40 x - 45 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 45 x^{2} + 40 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 45 ) \cdot 100}{2 ( - 45 )}

4 0^{2} - 4 (- 45) \cdot 100 = 140

x_{1, 2} = \frac{- 40 \pm 140}{2 ( - 45 )}

Separate the solutions

x_{1} = \frac{- 40 + 140}{2 ( - 45 )}, x_{2} = \frac{- 40 - 140}{2 ( - 45 )}

x = \frac{- 40 + 140}{2 ( - 45 )} : - \frac{10}{9}

x = \frac{- 40 - 140}{2 ( - 45 )} : 2

The solutions to the quadratic equation are:

x = - \frac{10}{9}, x = 2

2 (x + 2) - 3 (5 - x) = x + 5 (x - 3)

12 \cdot \frac{1}{2}

(2 x - 4)^{2} = 23

(x^{\frac{5}{9}})^{\frac{2}{3}}

∣ 3 x - 1 ∣ < 2 x + 5

What are the solutions to the equation 1+0.4x-0.45x^2=0 ?
The solutions to the equation 1+0.4x-0.45x^2=0 are x=-10/9 ,x=2
Find the zeros of 1+0.4x-0.45x^2=0
The zeros of 1+0.4x-0.45x^2=0 are x=-10/9 ,x=2