What is (2s^2-5st-t^2)-(s^2+7st-t^2) ?

The solution to (2s^2-5st-t^2)-(s^2+7st-t^2) is s^2-12st

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simplify (2s^2-5st-t^2)-(s^2+7st-t^2)

simplify

(2 s^{2} - 5 s t - t^{2}) - (s^{2} + 7 s t - t^{2})

s^{2} - 12 s t

Solution steps

(2 s^{2} - 5 s t - t^{2}) - (s^{2} + 7 s t - t^{2})

Apply rule:

(a) = a

(2 s^{2} - 5 s t - t^{2}) = 2 s^{2} - 5 s t - t^{2}

= 2 s^{2} - 5 s t - t^{2} - (s^{2} + 7 s t - t^{2})

Apply the distributive law:

- (a + b) = - a - b

- (s^{2} + 7 s t - t^{2}) = - s^{2} - 7 s t + t^{2}

= 2 s^{2} - 5 s t - t^{2} - s^{2} - 7 s t + t^{2}

Group like terms

= 2 s^{2} - s^{2} - 5 s t - 7 s t - t^{2} + t^{2}

Add similar elements:

2 s^{2} - s^{2} = s^{2}

= s^{2} - 5 s t - 7 s t - t^{2} + t^{2}

Add similar elements:

- 5 s t - 7 s t = - 12 s t

= s^{2} - 12 s t - t^{2} + t^{2}

Add similar elements:

- t^{2} + t^{2} = 0

= s^{2} - 12 s t

\frac{25 !}{3 ! ( 25 - 3 ) !}

\frac{1}{3} \cdot \frac{1}{5}

(x - 4) (x + 3) < 0

- 3 ∣ x + 1 ∣ + 4 = 1

- (\frac{1}{8})^{- 2}

What is (2s^2-5st-t^2)-(s^2+7st-t^2) ?
The solution to (2s^2-5st-t^2)-(s^2+7st-t^2) is s^2-12st