What are the solutions to the equation 37=2x^2-40 ?

The solutions to the equation 37=2x^2-40 are x=sqrt(77/2),x=-sqrt(77/2)

Find the zeros of 37=2x^2-40

The zeros of 37=2x^2-40 are x=sqrt(77/2),x=-sqrt(77/2)

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37 = 2 x^{2} - 40

x = \frac{77}{2}, x = - \frac{77}{2}

Decimal Notation

x = 6.20483 \dots, x = - 6.20483 \dots

Solution steps

37 = 2 x^{2} - 40

Switch sides

2 x^{2} - 40 = 37

Move

40

to the right side

2 x^{2} = 77

Divide both sides by

2

x^{2} = \frac{77}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{77}{2}, x = - \frac{77}{2}

- 2 (b + 5) = 4

\frac{33 !}{( 33 - 6 ) !}

(x - 1) \cdot (x - 2) \cdot (x + 2) \cdot (x + 3) - 5

5 x^{2} - 24 = 0

(x^{\frac{3}{2}})^{\frac{1}{2}}

What are the solutions to the equation 37=2x^2-40 ?
The solutions to the equation 37=2x^2-40 are x=sqrt(77/2),x=-sqrt(77/2)
Find the zeros of 37=2x^2-40
The zeros of 37=2x^2-40 are x=sqrt(77/2),x=-sqrt(77/2)