What is |(2x-1)/(1-x)|<= x-3 ?

The solution to |(2x-1)/(1-x)| = 3+sqrt(5)

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|(2x-1)/(1-x)|<= x-3

\frac{2 x - 1}{1 - x} \leq x - 3

x \geq 3 + 5

Interval Notation

[3 + 5, \infty)

Decimal Notation

x \geq 5.23606 \dots

Solution steps

\frac{2 x - 1}{1 - x} \leq x - 3

Find positive and negative intervals

x < \frac{1}{2}, \frac{1}{2} \leq x < 1, x \geq 1

Solve the inequality for each interval

No Solution or x \geq 3 + 5

Merge Overlapping Intervals

x \geq 3 + 5

x^{3} + x^{2} + 64 x + 64 > 0

r^{3} + 27

\frac{1}{2} m + \frac{2}{3} \leq \frac{2}{3} m + 2

(- \frac{3}{4} c)^{3}

4 x - 8 = 16

What is |(2x-1)/(1-x)|<= x-3 ?
The solution to |(2x-1)/(1-x)|<= x-3 is x>= 3+sqrt(5)