What are the solutions to the equation x^2+16x+64=36 ?

The solutions to the equation x^2+16x+64=36 are x=-2,x=-14

Find the zeros of x^2+16x+64=36

The zeros of x^2+16x+64=36 are x=-2,x=-14

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x^{2} + 16 x + 64 = 36

x = - 2, x = - 14

Solution steps

x^{2} + 16 x + 64 = 36

Move

36

to the left side

x^{2} + 16 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 28 = 12

x_{1, 2} = \frac{- 16 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 12}{2 \cdot 1}, x_{2} = \frac{- 16 - 12}{2 \cdot 1}

x = \frac{- 16 + 12}{2 \cdot 1} : - 2

x = \frac{- 16 - 12}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = - 2, x = - 14

n - 5 \leq 3

(\frac{1}{3} x^{4} y^{- 3})^{- 2}

\frac{6}{5} + \frac{5}{7} - 1

a^{3} - 5 a^{2} - 9 a + 45

p^{2} + 8 p + 12

What are the solutions to the equation x^2+16x+64=36 ?
The solutions to the equation x^2+16x+64=36 are x=-2,x=-14
Find the zeros of x^2+16x+64=36
The zeros of x^2+16x+64=36 are x=-2,x=-14