What is the answer to |2r+3|=|5r-17| ?

The answer to |2r+3|=|5r-17| is r=2\lor r= 20/3

Solve for r: |2r+3|=|5r-17|

The solution is r=2\lor r= 20/3

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∣ 2 r + 3 ∣ = ∣ 5 r - 17 ∣

r = 2 or r = \frac{20}{3}

Decimal Notation

r = 2, r = 6.66666 \dots

Solution steps

∣ 2 r + 3 ∣ = ∣ 5 r - 17 ∣

Find positive and negative intervals

r < - \frac{3}{2}, - \frac{3}{2} \leq r < \frac{17}{5}, r \geq \frac{17}{5}

Solve the inequality for each interval

No Solution or r = 2 or r = \frac{20}{3}

r = 2 or r = \frac{20}{3}

9 x + 3 = 21

t^{2} + t = 20

(3 u)^{2}

v = 32 (2.9)

49 a^{2} - b^{2}

What is the answer to |2r+3|=|5r-17| ?
The answer to |2r+3|=|5r-17| is r=2\lor r= 20/3
Solve for r: |2r+3|=|5r-17|
The solution is r=2\lor r= 20/3