What are the solutions to the equation x^2+0^2+4x-10(0)+4=0 ?

The solutions to the equation x^2+0^2+4x-10(0)+4=0 are x=-2

Find the zeros of x^2+0^2+4x-10(0)+4=0

The zeros of x^2+0^2+4x-10(0)+4=0 are x=-2

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x^{2} + 0^{2} + 4 x - 10 (0) + 4 = 0

x = - 2

Solution steps

x^{2} + 0^{2} + 4 x - 10 (0) + 4 = 0

Expand

x^{2} + 0^{2} + 4 x - 10 (0) + 4 : x^{2} + 4 x + 4

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

\frac{3}{5} (\frac{3}{5})

3 h^{8} - 46 h^{4} z^{2} - 32 z^{4}

∣ x - 2 ∣ = ∣ x + 1 ∣

(- 4 - 5 i) \cdot (1 - i)

What are the solutions to the equation x^2+0^2+4x-10(0)+4=0 ?
The solutions to the equation x^2+0^2+4x-10(0)+4=0 are x=-2
Find the zeros of x^2+0^2+4x-10(0)+4=0
The zeros of x^2+0^2+4x-10(0)+4=0 are x=-2