What are the solutions to the equation 2n^2-24n+72=0 ?

The solutions to the equation 2n^2-24n+72=0 are n=6

Find the zeros of 2n^2-24n+72=0

The zeros of 2n^2-24n+72=0 are n=6

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2 n^{2} - 24 n + 72 = 0

n = 6

Solution steps

2 n^{2} - 24 n + 72 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 \cdot 72}{2 \cdot 2}

(- 24)^{2} - 4 \cdot 2 \cdot 72 = 0

n_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 2}

n = \frac{- ( - 24 )}{2 \cdot 2}

\frac{- ( - 24 )}{2 \cdot 2} = 6

n = 6

The solution to the quadratic equation is:

n = 6

\frac{3 - 2 x}{2 + x} \leq 4

\frac{x}{4} + 10 = - 3

\frac{0}{1}

- 3 s \geq 33

6 = - s + 77

What are the solutions to the equation 2n^2-24n+72=0 ?
The solutions to the equation 2n^2-24n+72=0 are n=6
Find the zeros of 2n^2-24n+72=0
The zeros of 2n^2-24n+72=0 are n=6