What are the solutions to the equation x^2= 25/36 ?

The solutions to the equation x^2= 25/36 are x= 5/6 ,x=-5/6

Find the zeros of x^2= 25/36

The zeros of x^2= 25/36 are x= 5/6 ,x=-5/6

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x^{2} = \frac{25}{36}

x = \frac{5}{6}, x = - \frac{5}{6}

Decimal Notation

x = 0.83333 \dots, x = - 0.83333 \dots

Solution steps

x^{2} = \frac{25}{36}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{36}, x = - \frac{25}{36}

\frac{25}{36} = \frac{5}{6}

- \frac{25}{36} = - \frac{5}{6}

x = \frac{5}{6}, x = - \frac{5}{6}

(\frac{1}{6}) \cdot 2^{5}

\frac{( x + 8 )}{5} - \frac{2 x + 6}{4} \geq 2

1 + \frac{1}{1 + \frac{1}{1 + \frac{1}{2}}}

x^{2} = - x + 1

\frac{1}{2} 96

What are the solutions to the equation x^2= 25/36 ?
The solutions to the equation x^2= 25/36 are x= 5/6 ,x=-5/6
Find the zeros of x^2= 25/36
The zeros of x^2= 25/36 are x= 5/6 ,x=-5/6