What are the solutions to the equation 4x^2+6=34 ?

The solutions to the equation 4x^2+6=34 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 4x^2+6=34

The zeros of 4x^2+6=34 are x=sqrt(7),x=-sqrt(7)

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4 x^{2} + 6 = 34

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

4 x^{2} + 6 = 34

Move

6

to the right side

4 x^{2} = 28

Divide both sides by

4

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

4 3^{2}

\frac{15 ab}{4} \cdot \frac{8}{9 a ^{2} b ^{2}}

\frac{- 2 - ( - 8 )}{- 1 - 2}

7 w + 5 = 3 w - 15

What are the solutions to the equation 4x^2+6=34 ?
The solutions to the equation 4x^2+6=34 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 4x^2+6=34
The zeros of 4x^2+6=34 are x=sqrt(7),x=-sqrt(7)