What is (20x^2y^3z)/(24xy^4z^2) ?

The solution to (20x^2y^3z)/(24xy^4z^2) is (5x)/(6yz)

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simplify (20x^2y^3z)/(24xy^4z^2)

simplify

\frac{20 x ^{2} y ^{3} z}{24 x y ^{4} z ^{2}}

\frac{5 x}{6 yz}

Solution steps

\frac{20 x ^{2} y ^{3} z}{24 x y ^{4} z ^{2}}

Factor the number:

20 = 4 \cdot 5

= \frac{4 \cdot 5 x ^{2} y ^{3} z}{24 x y ^{4} z ^{2}}

Factor the number:

24 = 4 \cdot 6

= \frac{4 \cdot 5 x ^{2} y ^{3} z}{4 \cdot 6 x y ^{4} z ^{2}}

Cancel the common factor:

4

= \frac{5 x ^{2} y ^{3} z}{6 x y ^{4} z ^{2}}

Simplify

\frac{x ^{2}}{x} : x

= \frac{5 x y ^{3} z}{6 y ^{4} z ^{2}}

Simplify

\frac{y ^{3}}{y ^{4}} : \frac{1}{y}

= \frac{5 x z}{6 y z ^{2}}

Simplify

\frac{z}{z ^{2}} : \frac{1}{z}

= \frac{5 x}{6 yz}

19 x + 6 > 7 x + 10 or - 10 + 8 x \geq 12 x - 6

4 a < 12

x^{2} - x - 56 < 0

\frac{- 2 x + 6}{x ^{2} - 9}

(\frac{q ^{- 1} r s ^{- 2}}{r ^{- 5} s q ^{- 8}})^{- 1}

What is (20x^2y^3z)/(24xy^4z^2) ?
The solution to (20x^2y^3z)/(24xy^4z^2) is (5x)/(6yz)