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Popular >

x^2<x^2ln(x+1)

Solution

x^{2} < x^{2} ln (x + 1)

Solution

x > e - 1

+2

Interval Notation

(e - 1, \infty)

Decimal Notation

x > 1.71828 \dots

Solution steps

x^{2} < x^{2} ln (x + 1)

Move

x^{2} ln (x + 1)

to the left side

x^{2} - x^{2} ln (x + 1) < 0

Factor

x^{2} - x^{2} ln (x + 1) : - x^{2} (ln (x + 1) - 1)

- x^{2} (ln (x + 1) - 1) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- x^{2} (ln (x + 1) - 1)) (- 1) > 0 \cdot (- 1)

Refine

x^{2} (ln (x + 1) - 1) > 0

Identify the intervals

x > e - 1

Popular Examples

((x+3))/2 >= 3/4

\frac{( x + 3 )}{2} \geq \frac{3}{4}

simplify (2+i)/(3-2i)simplify

\frac{2 + i}{3 - 2 i}

4 x = 24

factor 6x+14 factor

6 x + 14

7 > ∣ 2 x - 3 ∣ \geq 3

Frequently Asked Questions (FAQ)

What is x^2<x^2ln(x+1) ?
The solution to x^2<x^2ln(x+1) is x>e-1