What is the answer to |6y+5|-17=0 ?

The answer to |6y+5|-17=0 is y=-11/3 \lor y=2

Solve for y: |6y+5|-17=0

The solution is y=-11/3 \lor y=2

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∣ 6 y + 5 ∣ - 17 = 0

y = - \frac{11}{3} or y = 2

Decimal Notation

y = - 3.66666 \dots, y = 2

Solution steps

∣ 6 y + 5 ∣ - 17 = 0

Move

17

to the right side

∣ 6 y + 5 ∣ = 17

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

6 y + 5 = - 17 or 6 y + 5 = 17

6 y + 5 = - 17 or 6 y + 5 = 17

y = - \frac{11}{3} or y = 2

24 a^{2} b^{2} + 16 a b^{4} + 64 a b^{3}

1 - e^{- 3}

x^{2} + 3 x + \frac{1}{4} = 0

∣ 2 x - 1 ∣ = (x + 2) - ∣ x - 5 ∣

5 x^{3} - 45 x^{2} + 100 x

What is the answer to |6y+5|-17=0 ?
The answer to |6y+5|-17=0 is y=-11/3 \lor y=2
Solve for y: |6y+5|-17=0
The solution is y=-11/3 \lor y=2