What are the solutions to the equation 6^2+1^2=c^2 ?

The solutions to the equation 6^2+1^2=c^2 are c=sqrt(37),c=-sqrt(37)

Find the zeros of 6^2+1^2=c^2

The zeros of 6^2+1^2=c^2 are c=sqrt(37),c=-sqrt(37)

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6^{2} + 1^{2} = c^{2}

c = 37, c = - 37

Decimal Notation

c = 6.08276 \dots, c = - 6.08276 \dots

Solution steps

6^{2} + 1^{2} = c^{2}

Switch sides

c^{2} = 6^{2} + 1^{2}

Simplify

6^{2} + 1^{2} : 37

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 37, c = - 37

(\frac{1}{5})^{x}

(22)^{3}

5 x (x - 3) = 0

\frac{1}{4} - x = \frac{x}{8}

512 y^{3} + 125 z^{3}

What are the solutions to the equation 6^2+1^2=c^2 ?
The solutions to the equation 6^2+1^2=c^2 are c=sqrt(37),c=-sqrt(37)
Find the zeros of 6^2+1^2=c^2
The zeros of 6^2+1^2=c^2 are c=sqrt(37),c=-sqrt(37)