What are the solutions to the equation 0=-16t^2+64t+5 ?

The solutions to the equation 0=-16t^2+64t+5 are t=-(-8+sqrt(69))/4 ,t=(8+sqrt(69))/4

Find the zeros of 0=-16t^2+64t+5

The zeros of 0=-16t^2+64t+5 are t=-(-8+sqrt(69))/4 ,t=(8+sqrt(69))/4

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0 = - 16 t^{2} + 64 t + 5

t = - \frac{- 8 + 69}{4}, t = \frac{8 + 69}{4}

Decimal Notation

t = - 0.07665 \dots, t = 4.07665 \dots

Solution steps

0 = - 16 t^{2} + 64 t + 5

Switch sides

- 16 t^{2} + 64 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 5}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 5 = 869

t_{1, 2} = \frac{- 64 \pm 8 69}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 64 + 8 69}{2 ( - 16 )}, t_{2} = \frac{- 64 - 8 69}{2 ( - 16 )}

t = \frac{- 64 + 8 69}{2 ( - 16 )} : - \frac{- 8 + 69}{4}

t = \frac{- 64 - 8 69}{2 ( - 16 )} : \frac{8 + 69}{4}

The solutions to the quadratic equation are:

t = - \frac{- 8 + 69}{4}, t = \frac{8 + 69}{4}

- 56 - 8 x \geq 35 - 21 x

\frac{x - ( - 5 - 8.66 i )}{1} + \frac{x}{6 i} + \frac{x}{( 2 - 2 i )} = 0

x^{2} - 3 x - 28

5 e^{0}

\frac{π}{6} + 2 π

What are the solutions to the equation 0=-16t^2+64t+5 ?
The solutions to the equation 0=-16t^2+64t+5 are t=-(-8+sqrt(69))/4 ,t=(8+sqrt(69))/4
Find the zeros of 0=-16t^2+64t+5
The zeros of 0=-16t^2+64t+5 are t=-(-8+sqrt(69))/4 ,t=(8+sqrt(69))/4