What are the solutions to the equation x^2+8x+18=0 ?

The solutions to the equation x^2+8x+18=0 are x=-4+sqrt(2)i,x=-4-sqrt(2)i

Find the zeros of x^2+8x+18=0

The zeros of x^2+8x+18=0 are x=-4+sqrt(2)i,x=-4-sqrt(2)i

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x^{2} + 8 x + 18 = 0

x = - 4 + 2 i, x = - 4 - 2 i

Solution steps

x^{2} + 8 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 18 : 22 i

x_{1, 2} = \frac{- 8 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 2 i}{2 \cdot 1}

x = \frac{- 8 + 2 2 i}{2 \cdot 1} : - 4 + 2 i

x = \frac{- 8 - 2 2 i}{2 \cdot 1} : - 4 - 2 i

The solutions to the quadratic equation are:

x = - 4 + 2 i, x = - 4 - 2 i

- \frac{2}{3} + 4

5 x + 4 = 49

\frac{6 x - 1}{5} = \frac{3}{1}

\frac{25}{3}

5 y + 6 = 4 y + 11

What are the solutions to the equation x^2+8x+18=0 ?
The solutions to the equation x^2+8x+18=0 are x=-4+sqrt(2)i,x=-4-sqrt(2)i
Find the zeros of x^2+8x+18=0
The zeros of x^2+8x+18=0 are x=-4+sqrt(2)i,x=-4-sqrt(2)i