What is |4x-2|>= x+1 ?

The solution to |4x-2|>= x+1 is x = 1

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|4x-2|>= x+1

∣ 4 x - 2 ∣ \geq x + 1

x \leq \frac{1}{5} or x \geq 1

Interval Notation

(- \infty, \frac{1}{5}] \cup [1, \infty)

Decimal Notation

x \leq 0.2 or x \geq 1

Solution steps

∣ 4 x - 2 ∣ \geq x + 1

Find positive and negative intervals

x < \frac{1}{2}, x \geq \frac{1}{2}

Solve the inequality for each interval

x \leq \frac{1}{5} or x \geq 1

4 x - 3 < 5

\frac{- 9 a ^{5} b ^{8}}{3 a ^{2} b ^{4}}

\frac{4}{15}

5 x^{4} + 20 x^{3} - 105 x^{2}