What are the solutions to the equation h^2-17h=-60 ?

The solutions to the equation h^2-17h=-60 are h=12,h=5

Find the zeros of h^2-17h=-60

The zeros of h^2-17h=-60 are h=12,h=5

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h^{2} - 17 h = - 60

h = 12, h = 5

Solution steps

h^{2} - 17 h = - 60

Move

60

to the left side

h^{2} - 17 h + 60 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 60 = 7

h_{1, 2} = \frac{- ( - 17 ) \pm 7}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 17 ) + 7}{2 \cdot 1}, h_{2} = \frac{- ( - 17 ) - 7}{2 \cdot 1}

h = \frac{- ( - 17 ) + 7}{2 \cdot 1} : 12

h = \frac{- ( - 17 ) - 7}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

h = 12, h = 5

x^{3} + 2 x^{2} + 16 x + 32

\frac{3}{7} - \frac{4}{5}

x^{2} + x - 1 = 1

\frac{2}{3} x + \frac{3}{2} (x - 5) \leq x

x^{4} - 2 x^{3} + 27 x - 54

What are the solutions to the equation h^2-17h=-60 ?
The solutions to the equation h^2-17h=-60 are h=12,h=5
Find the zeros of h^2-17h=-60
The zeros of h^2-17h=-60 are h=12,h=5