What are the solutions to the equation x(2x+4)=0 ?

The solutions to the equation x(2x+4)=0 are x=0,x=-2

Find the zeros of x(2x+4)=0

The zeros of x(2x+4)=0 are x=0,x=-2

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x (2 x + 4) = 0

x = 0, x = - 2

Solution steps

x (2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 4 = 0

Solve

2 x + 4 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

2 x + 12 \leq 2 x + 12

8 - 2 x \leq 2

\frac{x ^{2} - 16}{x ^{2} - 36} \leq 0

\frac{9}{3} + 4

- 2 + 3 (6) \geq \frac{1}{3}

What are the solutions to the equation x(2x+4)=0 ?
The solutions to the equation x(2x+4)=0 are x=0,x=-2
Find the zeros of x(2x+4)=0
The zeros of x(2x+4)=0 are x=0,x=-2