What are the solutions to the equation a^2+16a+6=7 ?

The solutions to the equation a^2+16a+6=7 are a=-8+sqrt(65),a=-8-sqrt(65)

Find the zeros of a^2+16a+6=7

The zeros of a^2+16a+6=7 are a=-8+sqrt(65),a=-8-sqrt(65)

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a^{2} + 16 a + 6 = 7

a = - 8 + 65, a = - 8 - 65

Solution steps

a^{2} + 16 a + 6 = 7

Move

7

to the left side

a^{2} + 16 a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 1) = 265

a_{1, 2} = \frac{- 16 \pm 2 65}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 16 + 2 65}{2 \cdot 1}, a_{2} = \frac{- 16 - 2 65}{2 \cdot 1}

a = \frac{- 16 + 2 65}{2 \cdot 1} : - 8 + 65

a = \frac{- 16 - 2 65}{2 \cdot 1} : - 8 - 65

The solutions to the quadratic equation are:

a = - 8 + 65, a = - 8 - 65

\frac{2 ^{5}}{4}

\frac{3}{4} (4 c - 12)

y^{2} - y - 12 = 0

1.5 q = - 8.4

5 x - (5 x - 148) = 148

What are the solutions to the equation a^2+16a+6=7 ?
The solutions to the equation a^2+16a+6=7 are a=-8+sqrt(65),a=-8-sqrt(65)
Find the zeros of a^2+16a+6=7
The zeros of a^2+16a+6=7 are a=-8+sqrt(65),a=-8-sqrt(65)