What are the solutions to the equation 2a^2-a-13=2 ?

The solutions to the equation 2a^2-a-13=2 are a=3,a=-5/2

Find the zeros of 2a^2-a-13=2

The zeros of 2a^2-a-13=2 are a=3,a=-5/2

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2 a^{2} - a - 13 = 2

a = 3, a = - \frac{5}{2}

Solution steps

2 a^{2} - a - 13 = 2

Move

2

to the left side

2 a^{2} - a - 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 15) = 11

a_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 2}, a_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 2}

a = \frac{- ( - 1 ) + 11}{2 \cdot 2} : 3

a = \frac{- ( - 1 ) - 11}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

a = 3, a = - \frac{5}{2}

(- x^{2})^{2}

\frac{u - 3}{9} = 1

\frac{1}{2 π}

(x + 5) (x + 3) (x - 7) > 0

\frac{4 x}{5} - \frac{x}{4} = 3

What are the solutions to the equation 2a^2-a-13=2 ?
The solutions to the equation 2a^2-a-13=2 are a=3,a=-5/2
Find the zeros of 2a^2-a-13=2
The zeros of 2a^2-a-13=2 are a=3,a=-5/2