What are the solutions to the equation n^2-5n+4=0 ?

The solutions to the equation n^2-5n+4=0 are n=4,n=1

Find the zeros of n^2-5n+4=0

The zeros of n^2-5n+4=0 are n=4,n=1

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n^{2} - 5 n + 4 = 0

n = 4, n = 1

Solution steps

n^{2} - 5 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

n_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

n = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

n = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

n = 4, n = 1

35 + 0.2 m \leq 89

y^{2} + 7 y + 12 = 0

x + 9 = 2 (x - 1)^{2}

1 < 1 - \frac{1}{6} x < 4

15 + 7 x \geq 2 x - 5

What are the solutions to the equation n^2-5n+4=0 ?
The solutions to the equation n^2-5n+4=0 are n=4,n=1
Find the zeros of n^2-5n+4=0
The zeros of n^2-5n+4=0 are n=4,n=1