What are the solutions to the equation 4x^2=-32x ?

The solutions to the equation 4x^2=-32x are x=0,x=-8

Find the zeros of 4x^2=-32x

The zeros of 4x^2=-32x are x=0,x=-8

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4 x^{2} = - 32 x

x = 0, x = - 8

Solution steps

4 x^{2} = - 32 x

Move

32 x

to the left side

4 x^{2} + 32 x = 0

Factor

4 x^{2} + 32 x : 4 x (x + 8)

4 x (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 8 = 0

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

\frac{π}{6} \cdot 2

5 = \frac{4 x + 23}{3}

x = \frac{26}{10} - \frac{8}{10} (- 3)

3 x^{5} - 18 x^{3} + 27 x

3 x y - 6 x^{2} y + x y + 4 x^{2} y

What are the solutions to the equation 4x^2=-32x ?
The solutions to the equation 4x^2=-32x are x=0,x=-8
Find the zeros of 4x^2=-32x
The zeros of 4x^2=-32x are x=0,x=-8