What is (6n^2+8n+2)/(2n^2-2) ?

The solution to (6n^2+8n+2)/(2n^2-2) is (3n+1)/(n-1)

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simplify (6n^2+8n+2)/(2n^2-2)

simplify

\frac{6 n ^{2} + 8 n + 2}{2 n ^{2} - 2}

\frac{3 n + 1}{n - 1}

Solution steps

\frac{6 n ^{2} + 8 n + 2}{2 n ^{2} - 2}

Factor

6 n^{2} + 8 n + 2 : 2 (3 n + 1) (n + 1)

= \frac{2 ( 3 n + 1 ) ( n + 1 )}{2 n ^{2} - 2}

Factor

2 n^{2} - 2 : 2 (n + 1) (n - 1)

= \frac{2 ( 3 n + 1 ) ( n + 1 )}{2 ( n + 1 ) ( n - 1 )}

Cancel the common factor:

2

= \frac{( 3 n + 1 ) ( n + 1 )}{( n + 1 ) ( n - 1 )}

Cancel the common factor:

n + 1

= \frac{3 n + 1}{n - 1}

5 \cdot 3 \cdot 2

3 x - 5 \geq 8 x + 7

100 a^{2} - 81 b^{2}

x^{3} + 13 x^{2} + 34 x - 48

\frac{- 3}{2} + 2

What is (6n^2+8n+2)/(2n^2-2) ?
The solution to (6n^2+8n+2)/(2n^2-2) is (3n+1)/(n-1)