What is the answer to 2(-3(z+1))-2(z+4)+4(-4)=2 ?

The answer to 2(-3(z+1))-2(z+4)+4(-4)=2 is z=-4

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2(-3(z+1))-2(z+4)+4(-4)=2

2 (- 3 (z + 1)) - 2 (z + 4) + 4 (- 4) = 2

z = - 4

Solution steps

2 (- 3 (z + 1)) - 2 (z + 4) + 4 (- 4) = 2

Remove parentheses:

(- a) = - a

- 2 \cdot 3 (z + 1) - 2 (z + 4) - 4 \cdot 4 = 2

Multiply the numbers:

2 \cdot 3 = 6

- 6 (z + 1) - 2 (z + 4) - 4 \cdot 4 = 2

Multiply the numbers:

4 \cdot 4 = 16

- 6 (z + 1) - 2 (z + 4) - 16 = 2

Move

16

to the right side

- 6 (z + 1) - 2 (z + 4) = 18

Expand

- 6 (z + 1) - 2 (z + 4) : - 8 z - 14

- 8 z - 14 = 18

Move

14

to the right side

- 8 z = 32

Divide both sides by

- 8

z = - 4

5 x^{2} - 28 x + 32 = 0

(- 3 + 4 i)^{2}

x - 0.8 x = 16

(x + 3)^{2} = 64

5 a + 5 < - 6

What is the answer to 2(-3(z+1))-2(z+4)+4(-4)=2 ?
The answer to 2(-3(z+1))-2(z+4)+4(-4)=2 is z=-4
Solve for z: 2(-3(z+1))-2(z+4)+4(-4)=2
The solution is z=-4