What is the answer to r=sqrt((-2\sqrt{3))^2+(2)^2} ?

The answer to r=sqrt((-2\sqrt{3))^2+(2)^2} is r=4

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r=sqrt((-2\sqrt{3))^2+(2)^2}

r = (- 23)^{2} + (2)^{2}

r = 4

Solution steps

r = (- 23)^{2} + (2)^{2}

Simplify

(- 23)^{2} + 2^{2} : 4

r = 4

49 \cdot 3

\frac{2}{3} \cdot 3

\frac{3 - x}{5} + \frac{1 + x}{4} \geq 2

ln (e^{3})

x^{3} + 2 x^{2} - 4 x \leq 8

What is the answer to r=sqrt((-2\sqrt{3))^2+(2)^2} ?
The answer to r=sqrt((-2\sqrt{3))^2+(2)^2} is r=4
Solve for r: r=sqrt((-2\sqrt{3))^2+(2)^2}
The solution is r=4