What are the solutions to the equation 3a^2-12a+8=71 ?

The solutions to the equation 3a^2-12a+8=71 are a=7,a=-3

Find the zeros of 3a^2-12a+8=71

The zeros of 3a^2-12a+8=71 are a=7,a=-3

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3 a^{2} - 12 a + 8 = 71

a = 7, a = - 3

Solution steps

3 a^{2} - 12 a + 8 = 71

Move

71

to the left side

3 a^{2} - 12 a - 63 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 63 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 63) = 30

a_{1, 2} = \frac{- ( - 12 ) \pm 30}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 12 ) + 30}{2 \cdot 3}, a_{2} = \frac{- ( - 12 ) - 30}{2 \cdot 3}

a = \frac{- ( - 12 ) + 30}{2 \cdot 3} : 7

a = \frac{- ( - 12 ) - 30}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

a = 7, a = - 3

\frac{4}{3} + \frac{1}{3}

4 + \frac{2}{3}

\frac{1}{3} (9 y + 3) - 14 < - \frac{1}{2} (8 y - 2)

(1 + \frac{0.02}{2})^{2} - 1

2 \cdot \frac{5}{3}

What are the solutions to the equation 3a^2-12a+8=71 ?
The solutions to the equation 3a^2-12a+8=71 are a=7,a=-3
Find the zeros of 3a^2-12a+8=71
The zeros of 3a^2-12a+8=71 are a=7,a=-3