What are the solutions to the equation t^2-13t+30=0 ?

The solutions to the equation t^2-13t+30=0 are t=10,t=3

Find the zeros of t^2-13t+30=0

The zeros of t^2-13t+30=0 are t=10,t=3

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t^{2} - 13 t + 30 = 0

t = 10, t = 3

Solution steps

t^{2} - 13 t + 30 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 30 = 7

t_{1, 2} = \frac{- ( - 13 ) \pm 7}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 13 ) + 7}{2 \cdot 1}, t_{2} = \frac{- ( - 13 ) - 7}{2 \cdot 1}

t = \frac{- ( - 13 ) + 7}{2 \cdot 1} : 10

t = \frac{- ( - 13 ) - 7}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

t = 10, t = 3

2 (- \frac{3}{7})^{0}

2 x - 5 + 1 + x = + x - 6

\frac{2 ^{2}}{- 3}

14!

6 (v + 1) - 10 = 4 (v - 1) + 2 v

What are the solutions to the equation t^2-13t+30=0 ?
The solutions to the equation t^2-13t+30=0 are t=10,t=3
Find the zeros of t^2-13t+30=0
The zeros of t^2-13t+30=0 are t=10,t=3