What are the solutions to the equation 21=4x^2-11 ?

The solutions to the equation 21=4x^2-11 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 21=4x^2-11

The zeros of 21=4x^2-11 are x=2sqrt(2),x=-2sqrt(2)

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21 = 4 x^{2} - 11

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

21 = 4 x^{2} - 11

Switch sides

4 x^{2} - 11 = 21

Move

11

to the right side

4 x^{2} = 32

Divide both sides by

4

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

\frac{x ^{3}}{x ^{7}}

V = \frac{1}{5} π 4^{3}

y^{2} + 8 y - 2 y - 16

\frac{x - 5}{x - 4} < 0

\frac{33000000 \cdot 0.5}{62.42 \cdot 32.2 \cdot 750}

What are the solutions to the equation 21=4x^2-11 ?
The solutions to the equation 21=4x^2-11 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 21=4x^2-11
The zeros of 21=4x^2-11 are x=2sqrt(2),x=-2sqrt(2)