What are the solutions to the equation 5z^2+4z-1=0 ?

The solutions to the equation 5z^2+4z-1=0 are z= 1/5 ,z=-1

Find the zeros of 5z^2+4z-1=0

The zeros of 5z^2+4z-1=0 are z= 1/5 ,z=-1

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5 z^{2} + 4 z - 1 = 0

z = \frac{1}{5}, z = - 1

Decimal Notation

z = 0.2, z = - 1

Solution steps

5 z^{2} + 4 z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 1) = 6

z_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 5}

Separate the solutions

z_{1} = \frac{- 4 + 6}{2 \cdot 5}, z_{2} = \frac{- 4 - 6}{2 \cdot 5}

z = \frac{- 4 + 6}{2 \cdot 5} : \frac{1}{5}

z = \frac{- 4 - 6}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

z = \frac{1}{5}, z = - 1

15 x y + 30 x^{2} y^{2}

(3)^{3}

∣ 8 y - 1 ∣ \geq 4

\frac{10 π}{180}

33

What are the solutions to the equation 5z^2+4z-1=0 ?
The solutions to the equation 5z^2+4z-1=0 are z= 1/5 ,z=-1
Find the zeros of 5z^2+4z-1=0
The zeros of 5z^2+4z-1=0 are z= 1/5 ,z=-1