What is factor x^4-3x^3-6x^2+6x+8 ?

The solution to factor x^4-3x^3-6x^2+6x+8 is (x+1)(x-4)(x^2-2)

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factor x^4-3x^3-6x^2+6x+8

factor

x^{4} - 3 x^{3} - 6 x^{2} + 6 x + 8

(x + 1) (x - 4) (x^{2} - 2)

Solution steps

x^{4} - 3 x^{3} - 6 x^{2} + 6 x + 8

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 3 x ^{3} - 6 x ^{2} + 6 x + 8}{x + 1}

\frac{x ^{4} - 3 x ^{3} - 6 x ^{2} + 6 x + 8}{x + 1} = x^{3} - 4 x^{2} - 2 x + 8

= (x + 1) (x^{3} - 4 x^{2} - 2 x + 8)

Factor

x^{3} - 4 x^{2} - 2 x + 8 : (x - 4) (x^{2} - 2)

= (x + 1) (x - 4) (x^{2} - 2)

9 r^{4} - s^{4}

(\frac{7}{4} m^{- 2})^{2}

\frac{4 π}{2}

(0.006 q^{2}) + (22) = 80

2 x + 3 = 3 x - 4

What is factor x^4-3x^3-6x^2+6x+8 ?
The solution to factor x^4-3x^3-6x^2+6x+8 is (x+1)(x-4)(x^2-2)