What are the solutions to the equation 0=-16x^2+112x ?

The solutions to the equation 0=-16x^2+112x are x=0,x=7

Find the zeros of 0=-16x^2+112x

The zeros of 0=-16x^2+112x are x=0,x=7

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0 = - 16 x^{2} + 112 x

x = 0, x = 7

Solution steps

0 = - 16 x^{2} + 112 x

Switch sides

- 16 x^{2} + 112 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 112 \pm 11 2 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

11 2^{2} - 4 (- 16) \cdot 0 = 112

x_{1, 2} = \frac{- 112 \pm 112}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 112 + 112}{2 ( - 16 )}, x_{2} = \frac{- 112 - 112}{2 ( - 16 )}

x = \frac{- 112 + 112}{2 ( - 16 )} : 0

x = \frac{- 112 - 112}{2 ( - 16 )} : 7

The solutions to the quadratic equation are:

x = 0, x = 7

4 a^{2} - 9

\frac{3}{4} - (- \frac{1}{9})

9 u^{2} = - 30 u - 25

z^{2} - 9 z + 14

9 x^{2} - 3 x - 12 = 0

What are the solutions to the equation 0=-16x^2+112x ?
The solutions to the equation 0=-16x^2+112x are x=0,x=7
Find the zeros of 0=-16x^2+112x
The zeros of 0=-16x^2+112x are x=0,x=7