What are the solutions to the equation 9x^2-3x-12=0 ?

The solutions to the equation 9x^2-3x-12=0 are x= 4/3 ,x=-1

Find the zeros of 9x^2-3x-12=0

The zeros of 9x^2-3x-12=0 are x= 4/3 ,x=-1

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9 x^{2} - 3 x - 12 = 0

x = \frac{4}{3}, x = - 1

Decimal Notation

x = 1.33333 \dots, x = - 1

Solution steps

9 x^{2} - 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 12 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 12) = 21

x_{1, 2} = \frac{- ( - 3 ) \pm 21}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 21}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 21}{2 \cdot 9}

x = \frac{- ( - 3 ) + 21}{2 \cdot 9} : \frac{4}{3}

x = \frac{- ( - 3 ) - 21}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 1

5 (j - 4) + j = - 8

x^{2} - 14 x + 48 \leq 0

(- 5 x^{3} y)^{3}

\frac{11 \cdot 20 i}{11 + 20 i}

\frac{1}{2} + 3

What are the solutions to the equation 9x^2-3x-12=0 ?
The solutions to the equation 9x^2-3x-12=0 are x= 4/3 ,x=-1
Find the zeros of 9x^2-3x-12=0
The zeros of 9x^2-3x-12=0 are x= 4/3 ,x=-1