What is (-2f)/(d^5)((df^5)/(-2f^{10)})^2 ?

The solution to (-2f)/(d^5)((df^5)/(-2f^{10)})^2 is -1/(2d^3f^9)

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simplify (-2f)/(d^5)((df^5)/(-2f^{10)})^2

simplify

\frac{- 2 f}{d ^{5}} (\frac{d f ^{5}}{- 2 f ^{10}})^{2}

- \frac{1}{2 d ^{3} f ^{9}}

Solution steps

\frac{- 2 f}{d ^{5}} (\frac{d f ^{5}}{- 2 f ^{10}})^{2}

Simplify

(\frac{d f ^{5}}{- 2 f ^{10}})^{2} : \frac{d ^{2}}{4 f ^{10}}

= \frac{- 2 f}{d ^{5}} \cdot \frac{d ^{2}}{4 f ^{10}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 2 f}{d ^{5}} = - \frac{2 f}{d ^{5}}

= - \frac{2 f}{d ^{5}} \cdot \frac{d ^{2}}{4 f ^{10}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{2 f d ^{2}}{d ^{5} \cdot 4 f ^{10}}

Factor the number:

4 = 2 \cdot 2

= - \frac{2 f d ^{2}}{d ^{5} \cdot 2 \cdot 2 f ^{10}}

Cancel the common factor:

2

= - \frac{f d ^{2}}{d ^{5} \cdot 2 f ^{10}}

Simplify

\frac{f}{f ^{10}} : \frac{1}{f ^{9}}

= - \frac{d ^{2}}{d ^{5} \cdot 2 f ^{9}}

Simplify

\frac{d ^{2}}{d ^{5}} : \frac{1}{d ^{3}}

= - \frac{1}{d ^{3} \cdot 2 f ^{9}}

= - \frac{1}{2 d ^{3} f ^{9}}

45 r^{2} - 125

- x^{2} - 4 x - 5 = 0

x^{- \frac{11}{10}}

∣ 3 x + 4 ∣ = 2

6 X - 9 = 3 X - 3

What is (-2f)/(d^5)((df^5)/(-2f^{10)})^2 ?
The solution to (-2f)/(d^5)((df^5)/(-2f^{10)})^2 is -1/(2d^3f^9)