What are the solutions to the equation x^2+12x-1=9 ?

The solutions to the equation x^2+12x-1=9 are x=-6+sqrt(46),x=-6-sqrt(46)

Find the zeros of x^2+12x-1=9

The zeros of x^2+12x-1=9 are x=-6+sqrt(46),x=-6-sqrt(46)

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x^{2} + 12 x - 1 = 9

x = - 6 + 46, x = - 6 - 46

Decimal Notation

x = 0.78232 \dots, x = - 12.78232 \dots

Solution steps

x^{2} + 12 x - 1 = 9

Move

9

to the left side

x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 10) = 246

x_{1, 2} = \frac{- 12 \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 46}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 46}{2 \cdot 1}

x = \frac{- 12 + 2 46}{2 \cdot 1} : - 6 + 46

x = \frac{- 12 - 2 46}{2 \cdot 1} : - 6 - 46

The solutions to the quadratic equation are:

x = - 6 + 46, x = - 6 - 46

2 y = 6

1 + x - 53 = x^{2} - 2 x - 152 x

- 16 x > - 80

6 x^{2} + 48 x

x + 3 < 12

What are the solutions to the equation x^2+12x-1=9 ?
The solutions to the equation x^2+12x-1=9 are x=-6+sqrt(46),x=-6-sqrt(46)
Find the zeros of x^2+12x-1=9
The zeros of x^2+12x-1=9 are x=-6+sqrt(46),x=-6-sqrt(46)