What are the solutions to the equation 0=3t^2-24t+36 ?

The solutions to the equation 0=3t^2-24t+36 are t=6,t=2

Find the zeros of 0=3t^2-24t+36

The zeros of 0=3t^2-24t+36 are t=6,t=2

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0 = 3 t^{2} - 24 t + 36

t = 6, t = 2

Solution steps

0 = 3 t^{2} - 24 t + 36

Switch sides

3 t^{2} - 24 t + 36 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 36}{2 \cdot 3}

(- 24)^{2} - 4 \cdot 3 \cdot 36 = 12

t_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 3}, t_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 3}

t = \frac{- ( - 24 ) + 12}{2 \cdot 3} : 6

t = \frac{- ( - 24 ) - 12}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

t = 6, t = 2

- 2 (3 w + 6) - (4 w - 3) = 21

\frac{2}{n + 8} + \frac{4}{n + 1}

7 a c - 2 b d + b c - 14 a d

\frac{6 !}{4 ! ( 6 - 4 ) !}

10 0^{\frac{1}{2}}

What are the solutions to the equation 0=3t^2-24t+36 ?
The solutions to the equation 0=3t^2-24t+36 are t=6,t=2
Find the zeros of 0=3t^2-24t+36
The zeros of 0=3t^2-24t+36 are t=6,t=2