What is (-15r^6s^7t^4)/(3r^2s^9t^7) ?

The solution to (-15r^6s^7t^4)/(3r^2s^9t^7) is -(5r^4)/(s^2t^3)

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simplify (-15r^6s^7t^4)/(3r^2s^9t^7)

simplify

\frac{- 15 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

- \frac{5 r ^{4}}{s ^{2} t ^{3}}

Solution steps

\frac{- 15 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

Factor the number:

15 = 3 \cdot 5

= \frac{- 3 \cdot 5 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

Cancel the common factor:

3

= \frac{- 5 r ^{6} s ^{7} t ^{4}}{r ^{2} s ^{9} t ^{7}}

Simplify

\frac{r ^{6}}{r ^{2}} : r^{4}

= \frac{- 5 r ^{4} s ^{7} t ^{4}}{s ^{9} t ^{7}}

Simplify

\frac{s ^{7}}{s ^{9}} : \frac{1}{s ^{2}}

= \frac{- 5 r ^{4} t ^{4}}{s ^{2} t ^{7}}

Simplify

\frac{t ^{4}}{t ^{7}} : \frac{1}{t ^{3}}

= \frac{- 5 r ^{4}}{s ^{2} t ^{3}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{5 r ^{4}}{s ^{2} t ^{3}}

5 x^{2} + 3 x \geq 3 x^{2} + 20

x^{4} - y^{6}

- 5 t^{2} + 50 t + 5

lo g_{4} (\frac{1}{16}) = x

\frac{x}{2} \leq 6 - x

What is (-15r^6s^7t^4)/(3r^2s^9t^7) ?
The solution to (-15r^6s^7t^4)/(3r^2s^9t^7) is -(5r^4)/(s^2t^3)