What are the solutions to the equation 144-73x+4x^2=0 ?

The solutions to the equation 144-73x+4x^2=0 are x=16,x= 9/4

Find the zeros of 144-73x+4x^2=0

The zeros of 144-73x+4x^2=0 are x=16,x= 9/4

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144 - 73 x + 4 x^{2} = 0

x = 16, x = \frac{9}{4}

Decimal Notation

x = 16, x = 2.25

Solution steps

144 - 73 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 73 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 73 ) \pm ( - 73 ) ^{2} - 4 \cdot 4 \cdot 144}{2 \cdot 4}

(- 73)^{2} - 4 \cdot 4 \cdot 144 = 55

x_{1, 2} = \frac{- ( - 73 ) \pm 55}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 73 ) + 55}{2 \cdot 4}, x_{2} = \frac{- ( - 73 ) - 55}{2 \cdot 4}

x = \frac{- ( - 73 ) + 55}{2 \cdot 4} : 16

x = \frac{- ( - 73 ) - 55}{2 \cdot 4} : \frac{9}{4}

The solutions to the quadratic equation are:

x = 16, x = \frac{9}{4}

5 x^{2} + 10 x - 40

5 x^{2} - 10 x + 4 = 0

7 a - 14 a^{2} = 0

\frac{( n ( n + 1 ) ( 2 n + 1 ) )}{6} + (n + 1)^{2}

4 ∣ x + 8 ∣ - 5 = 11

What are the solutions to the equation 144-73x+4x^2=0 ?
The solutions to the equation 144-73x+4x^2=0 are x=16,x= 9/4
Find the zeros of 144-73x+4x^2=0
The zeros of 144-73x+4x^2=0 are x=16,x= 9/4