What are the solutions to the equation 5x^2+x+1=5 ?

The solutions to the equation 5x^2+x+1=5 are x= 4/5 ,x=-1

Find the zeros of 5x^2+x+1=5

The zeros of 5x^2+x+1=5 are x= 4/5 ,x=-1

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5 x^{2} + x + 1 = 5

x = \frac{4}{5}, x = - 1

Decimal Notation

x = 0.8, x = - 1

Solution steps

5 x^{2} + x + 1 = 5

Move

5

to the left side

5 x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 4) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 5}, x_{2} = \frac{- 1 - 9}{2 \cdot 5}

x = \frac{- 1 + 9}{2 \cdot 5} : \frac{4}{5}

x = \frac{- 1 - 9}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = - 1

(x + h)^{3} - x^{3}

3 x^{2} - x - 2 = - 2

2 x^{2} + 50 y^{2} - 20 x y

(- \frac{7}{4}) - \frac{2}{9}

\frac{1 - 6 i}{3 i}

What are the solutions to the equation 5x^2+x+1=5 ?
The solutions to the equation 5x^2+x+1=5 are x= 4/5 ,x=-1
Find the zeros of 5x^2+x+1=5
The zeros of 5x^2+x+1=5 are x= 4/5 ,x=-1