What are the solutions to the equation 2a^2+2a=4 ?

The solutions to the equation 2a^2+2a=4 are a=1,a=-2

Find the zeros of 2a^2+2a=4

The zeros of 2a^2+2a=4 are a=1,a=-2

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2 a^{2} + 2 a = 4

a = 1, a = - 2

Solution steps

2 a^{2} + 2 a = 4

Move

4

to the left side

2 a^{2} + 2 a - 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 4) = 6

a_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 2 + 6}{2 \cdot 2}, a_{2} = \frac{- 2 - 6}{2 \cdot 2}

a = \frac{- 2 + 6}{2 \cdot 2} : 1

a = \frac{- 2 - 6}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

a = 1, a = - 2

x^{2} = 3 6^{2}

13 x^{2} + 1 = 6 x

6 n^{2} - 54 = 0

\frac{x ^{7}}{x ^{4}}

7.2 - 3 c = 2 c - 2

What are the solutions to the equation 2a^2+2a=4 ?
The solutions to the equation 2a^2+2a=4 are a=1,a=-2
Find the zeros of 2a^2+2a=4
The zeros of 2a^2+2a=4 are a=1,a=-2