What are the solutions to the equation -3x^2+19=0 ?

The solutions to the equation -3x^2+19=0 are x=sqrt(19/3),x=-sqrt(19/3)

Find the zeros of -3x^2+19=0

The zeros of -3x^2+19=0 are x=sqrt(19/3),x=-sqrt(19/3)

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- 3 x^{2} + 19 = 0

x = \frac{19}{3}, x = - \frac{19}{3}

Decimal Notation

x = 2.51661 \dots, x = - 2.51661 \dots

Solution steps

- 3 x^{2} + 19 = 0

Move

19

to the right side

- 3 x^{2} = - 19

Divide both sides by

- 3

x^{2} = \frac{19}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{19}{3}, x = - \frac{19}{3}

x^{2} - 2 x = - 5

8 x - 16 \geq 4

\frac{5}{4} - \frac{1}{4}

\frac{3 π}{4} + 4 π

16 (t - 3) = - 16

What are the solutions to the equation -3x^2+19=0 ?
The solutions to the equation -3x^2+19=0 are x=sqrt(19/3),x=-sqrt(19/3)
Find the zeros of -3x^2+19=0
The zeros of -3x^2+19=0 are x=sqrt(19/3),x=-sqrt(19/3)