What are the solutions to the equation -x^2-x+8=0 ?

The solutions to the equation -x^2-x+8=0 are x=-(1+sqrt(33))/2 ,x=(sqrt(33)-1)/2

Find the zeros of -x^2-x+8=0

The zeros of -x^2-x+8=0 are x=-(1+sqrt(33))/2 ,x=(sqrt(33)-1)/2

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- x^{2} - x + 8 = 0

x = - \frac{1 + 33}{2}, x = \frac{33 - 1}{2}

Decimal Notation

x = - 3.37228 \dots, x = 2.37228 \dots

Solution steps

- x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 8}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 8 = 33

x_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 33}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 33}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 33}{2 ( - 1 )} : - \frac{1 + 33}{2}

x = \frac{- ( - 1 ) - 33}{2 ( - 1 )} : \frac{33 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 33}{2}, x = \frac{33 - 1}{2}

- 5 > z - 11

10 = - 2 k

- 34 < 3 z - 4 \leq 23

7 x = 49

(u + 5)^{2} - 72 = 0

What are the solutions to the equation -x^2-x+8=0 ?
The solutions to the equation -x^2-x+8=0 are x=-(1+sqrt(33))/2 ,x=(sqrt(33)-1)/2
Find the zeros of -x^2-x+8=0
The zeros of -x^2-x+8=0 are x=-(1+sqrt(33))/2 ,x=(sqrt(33)-1)/2