What are the solutions to the equation 2x^2+10x+8=0 ?

The solutions to the equation 2x^2+10x+8=0 are x=-1,x=-4

Find the zeros of 2x^2+10x+8=0

The zeros of 2x^2+10x+8=0 are x=-1,x=-4

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2 x^{2} + 10 x + 8 = 0

x = - 1, x = - 4

Solution steps

2 x^{2} + 10 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 8 = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 \cdot 2}, x_{2} = \frac{- 10 - 6}{2 \cdot 2}

x = \frac{- 10 + 6}{2 \cdot 2} : - 1

x = \frac{- 10 - 6}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

4 x - x^{2} - 3

k^{- \frac{1}{6}}

\frac{m ^{6} n ^{3}}{m ^{2} n ^{6}}

4 + 4

6 x^{5} \cdot 3 x^{5} \cdot x^{0}

What are the solutions to the equation 2x^2+10x+8=0 ?
The solutions to the equation 2x^2+10x+8=0 are x=-1,x=-4
Find the zeros of 2x^2+10x+8=0
The zeros of 2x^2+10x+8=0 are x=-1,x=-4