What are the solutions to the equation (4x+1)(x+2)=-2 ?

The solutions to the equation (4x+1)(x+2)=-2 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8

Find the zeros of (4x+1)(x+2)=-2

The zeros of (4x+1)(x+2)=-2 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8

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(4 x + 1) (x + 2) = - 2

x = \frac{- 9 + 17}{8}, x = \frac{- 9 - 17}{8}

Decimal Notation

x = - 0.60961 \dots, x = - 1.64038 \dots

Solution steps

(4 x + 1) (x + 2) = - 2

Expand

(4 x + 1) (x + 2) : 4 x^{2} + 9 x + 2

4 x^{2} + 9 x + 2 = - 2

Move

2

to the left side

4 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 4 = 17

x_{1, 2} = \frac{- 9 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 17}{2 \cdot 4}, x_{2} = \frac{- 9 - 17}{2 \cdot 4}

x = \frac{- 9 + 17}{2 \cdot 4} : \frac{- 9 + 17}{8}

x = \frac{- 9 - 17}{2 \cdot 4} : \frac{- 9 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 9 + 17}{8}, x = \frac{- 9 - 17}{8}

\frac{- 4}{3 2}

\frac{1}{4} x - \frac{2}{3} \leq x + 2

\frac{2}{x} - 10 \geq \frac{2}{24}

32 b^{2} + 40 b - 12

3456

What are the solutions to the equation (4x+1)(x+2)=-2 ?
The solutions to the equation (4x+1)(x+2)=-2 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8
Find the zeros of (4x+1)(x+2)=-2
The zeros of (4x+1)(x+2)=-2 are x=(-9+sqrt(17))/8 ,x=(-9-sqrt(17))/8