What are the solutions to the equation (2x+4)^2=9 ?

The solutions to the equation (2x+4)^2=9 are x=-1/2 ,x=-7/2

Find the zeros of (2x+4)^2=9

The zeros of (2x+4)^2=9 are x=-1/2 ,x=-7/2

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(2 x + 4)^{2} = 9

x = - \frac{1}{2}, x = - \frac{7}{2}

Decimal Notation

x = - 0.5, x = - 3.5

Solution steps

(2 x + 4)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 4 = 9 : x = - \frac{1}{2}

Solve

2 x + 4 = - 9 : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{7}{2}

\frac{50 !}{2 ! ( 48 ! )}

\frac{2}{5}

\frac{1}{6} \times \frac{5}{6} + \frac{5}{6} \times \frac{1}{6}

4 x^{2} + 4 x + 1 = 0

32 + 4 x = - 13

What are the solutions to the equation (2x+4)^2=9 ?
The solutions to the equation (2x+4)^2=9 are x=-1/2 ,x=-7/2
Find the zeros of (2x+4)^2=9
The zeros of (2x+4)^2=9 are x=-1/2 ,x=-7/2