What is factor a^{10}-28a^5+27 ?

The solution to factor a^{10}-28a^5+27 is (a-1)(a^4+a^3+a^2+a+1)(a^5-27)

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factor a^{10}-28a^5+27

factor

a^{10} - 28 a^{5} + 27

(a - 1) (a^{4} + a^{3} + a^{2} + a + 1) (a^{5} - 27)

Solution steps

a^{10} - 28 a^{5} + 27

Use the rational root theorem

= (a - 1) \frac{a ^{10} - 28 a ^{5} + 27}{a - 1}

\frac{a ^{10} - 28 a ^{5} + 27}{a - 1} = a^{9} + a^{8} + a^{7} + a^{6} + a^{5} - 27 a^{4} - 27 a^{3} - 27 a^{2} - 27 a - 27

= (a - 1) (a^{9} + a^{8} + a^{7} + a^{6} + a^{5} - 27 a^{4} - 27 a^{3} - 27 a^{2} - 27 a - 27)

Factor

a^{9} + a^{8} + a^{7} + a^{6} + a^{5} - 27 a^{4} - 27 a^{3} - 27 a^{2} - 27 a - 27 : (a^{4} + a^{3} + a^{2} + a + 1) (a^{5} - 27)

= (a - 1) (a^{4} + a^{3} + a^{2} + a + 1) (a^{5} - 27)

x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

w^{2} - 10 w + 25 = 0

3220

\frac{1}{11.73913} - \frac{1}{12}

9 q^{2} - 6 q + 1 = 0

What is factor a^{10}-28a^5+27 ?
The solution to factor a^{10}-28a^5+27 is (a-1)(a^4+a^3+a^2+a+1)(a^5-27)