What is ((3*2^n)*(3*8^n))/(3*16^{1-n)} ?

The solution to ((3*2^n)*(3*8^n))/(3*16^{1-n)} is 3*2^{8n-4}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((32^n)(38^n))/(316^{1-n)}

simplify

\frac{( 3 \cdot 2 ^{n} ) \cdot ( 3 \cdot 8 ^{n} )}{3 \cdot 1 6 ^{1 - n}}

3 \cdot 2^{8 n - 4}

Solution steps

\frac{( 3 \cdot 2 ^{n} ) ( 3 \cdot 8 ^{n} )}{3 \cdot 1 6 ^{1 - n}}

Cancel the common factor:

3

= \frac{2 ^{n} \cdot 3 \cdot 8 ^{n}}{1 6 ^{1 - n}}

Factor

1 6^{1 - n} : 2^{4 (1 - n)}

= \frac{2 ^{n} \cdot 3 \cdot 8 ^{n}}{2 ^{4 (1 - n)}}

Simplify

\frac{2 ^{n}}{2 ^{4 (1 - n)}} : 2^{5 n - 4}

= 2^{5 n - 4} \cdot 3 \cdot 8^{n}

Simplify

2^{5 n - 4} \cdot 8^{n} : 2^{8 n - 4}

= 2^{8 n - 4} \cdot 3

= 3 \cdot 2^{8 n - 4}

\frac{\frac{1}{1 + x + h} - \frac{1}{1 + x}}{h}

9 X + 7 = 52

6.7 x = 5.2 x + 12.3

x^{2} + \frac{4}{3} x + \frac{4}{9}

12 + 2 x \leq 5 (x + \frac{3}{5}) + 15

What is ((3*2^n)*(3*8^n))/(3*16^{1-n)} ?
The solution to ((3*2^n)*(3*8^n))/(3*16^{1-n)} is 3*2^{8n-4}