What are the solutions to the equation x^2+6x-13=3 ?

The solutions to the equation x^2+6x-13=3 are x=2,x=-8

Find the zeros of x^2+6x-13=3

The zeros of x^2+6x-13=3 are x=2,x=-8

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x^{2} + 6 x - 13 = 3

x = 2, x = - 8

Solution steps

x^{2} + 6 x - 13 = 3

Move

3

to the left side

x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 10}{2 \cdot 1}

x = \frac{- 6 + 10}{2 \cdot 1} : 2

x = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

- \frac{5}{16} + \frac{1}{4}

4 x + 11 < - 1 or x - 4 \geq - 2

\frac{- 2}{2 3}

9 y^{3} (- 13 x^{5})

x^{2} - 6 x + 5

What are the solutions to the equation x^2+6x-13=3 ?
The solutions to the equation x^2+6x-13=3 are x=2,x=-8
Find the zeros of x^2+6x-13=3
The zeros of x^2+6x-13=3 are x=2,x=-8